0=4.9t^2-14t-60

Solution for 0=4.9t^2-14t-60 equation:

0=4.9t^2-14t-60

We move all terms to the left:

0-(4.9t^2-14t-60)=0

We add all the numbers together, and all the variables

-(4.9t^2-14t-60)=0

We get rid of parentheses

-4.9t^2+14t+60=0

a = -4.9; b = 14; c = +60;
Δ = b2-4ac
Δ = 142-4·(-4.9)·60
Δ = 1372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1372}=\sqrt{196*7}=\sqrt{196}*\sqrt{7}=14\sqrt{7}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{7}}{2*-4.9}=\frac{-14-14\sqrt{7}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{7}}{2*-4.9}=\frac{-14+14\sqrt{7}}{-9.8}
$